How much momentum does a $\frac{1}{4} k g$ $1/4 kg$ object moving at $32 \frac{m}{s}$ $32 m/s$ have?

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How much momentum does a $\frac{1}{4} k g$ $1/4 kg$ object moving at $32 \frac{m}{s}$ $32 m/s$ have?

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Answer 1 · 2018-04-30T15:40:51

See explanation.

Explanation:

Momentum is calculated as a vector with value equal to product of velocity ( $v$ $v$ ) and mass ( $m$ $m$ ) and direction equal to the direction of velocity vector.

$\to p = m \cdot \to v$ $vec(p)=m*vec(v)$

Here the value is:

$p = \frac{1}{4} \cdot 32 = 8 [k g \cdot \frac{m}{s}]$ $p=1/432=8 [kgm/s]$

Answer 2 · 2018-04-30T15:51:56

$8 \ "kg m/s"$

Explanation:

Momentum of an object is given by the equation:

$p=mv$

$m$ is the mass of the object

$v$ is the velocity of the object

So, plugging in our given values into the equation, we get:

$p=1/4 \ "kg"*32 \ "m/s"$

$=8 \ "kg m/s"$

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How much momentum does a $\frac{1}{4} k g$ $1/4 kg$ object moving at $32 \frac{m}{s}$ $32 m/s$ have?

2 Answers

Explanation:

$\to p = m \cdot \to v$ $vec(p)=m*vec(v)$

$p = \frac{1}{4} \cdot 32 = 8 [k g \cdot \frac{m}{s}]$ $p=1/432=8 [kgm/s]$

Explanation:

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How much momentum does a 1/4 kg14kg1/4 kg object moving at 32 m/s32ms32 m/s have?

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Explanation:

vec(p)=m*vec(v)→p=m⋅→vvec(p)=m*vec(v)

p=1/4*32=8 [kg*m/s]p=14⋅32=8[kg⋅ms]p=1/4*32=8 [kg*m/s]

Explanation:

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Impact of this question

How much momentum does a $\frac{1}{4} k g$ $1/4 kg$ object moving at $32 \frac{m}{s}$ $32 m/s$ have?

$\to p = m \cdot \to v$ $vec(p)=m*vec(v)$

$p = \frac{1}{4} \cdot 32 = 8 [k g \cdot \frac{m}{s}]$ $p=1/432=8 [kgm/s]$