Evaluate 11P4?

1 Answer
May 1, 2018

#=11*10*9*8# which equals to:
#7920#

Explanation:

The formula for permutations is:
#P(n,r)=(n!)/((n−r))!# or in this form
#=_nP_r=(n!)/((n−r)!)#. Using the givens we know:
#n=11# and #r=4#. Inputting values:
#=_(11)P_4=(11!)/((11−4)!)# Simplifying:
#=_(11)P_4=(11!)/(7!)# Since #7! =7*6*5...# and #11! =11*10...*7*6*5...# we can cancel out the factors from 7 on down to get:
#=11*10*9*8# which equals to:
#7920#
Source (I forgot equation)