How do you find the x and y intercepts for #7x + 8y = 18#?

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Answer 1 · 2018-05-01T12:37:47

#:. y#-intercept = #18/8#

#:. x#-intercept = #18/7#

#x#-intercept means the point where the lines reaches the #x#-axis which means #y=0#

#y#-intercept means the point where the lines reaches the #y#-axis which means #x=0#

To find #y#-intercept, there is also another method which is by using the formulae itself, which is #y=mx+c# where #c# stands for #y#-intercept.

Regarding your question, to find #y#-intercept using
[#y=mx+c# method]

#=> 7x + 8y = 18#

#=> y = (18-7x)/8#

#=> y = (18)/8 - (7x)/8#

#=> y = -(7x)/8 + (18)/8#

#:. y#-intercept = #18/8#

Or apply #x=0#

#=> 8y = 18#

#:. y# -intercept = #18/8#

To find #x#-intercept, apply #y=0#

#=> 18/8 = (7x)/8#

#=> 144 = 56x#

#:. x#-intercept = #18/7#