Question

What is the phase shift for the function: `f( x ) = \sin ( 2x - \frac { \pi } { 3} ) + \frac { \pi } { 2}`?

Answer 1

`pi/6`

Explanation:

First, get the equation into the form:
`y=asinb(x-c)+d`. This requires factoring out `x`'s coefficeintL
`y=sin2(2/2x-pi/(3*2))+pi/2` Simplify:
`y=sin2(x-pi/6)+pi/2`

Since the phase shift is `-c`, and the `c` term is `-pi/6`, the phase shift is `pi/6`.