In the triangle below: ∠C = 90∘, AC = 2 and BC = 3. how do I solve it?

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Answer 1 · 2018-05-02T08:58:20

#:. sin (A) = 0.8320#

To find the value of #sin A#, we first must determine its angle.

Since #AC = 2 ; BC = 3#

By using #tan (O / A)#

#=> tan[ (BC)/(AC)]#

#=> tan (3/2)#

To find the value of angle, use #tan^-1# on your calculator

#=> tan^-1(3/2)#

#=> 56'19' degrees.#

Then, substitute A with the value found.

#=> sin(56'19')#

#:. sin (A) = 0.8320#