Given $F = \frac{G m_{1} m_{2}}{d}$ $F = (Gm_1m_2)/d$ , how do you solve for $G$ $G$ ?

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Answer 1 · 2018-05-02T16:29:40

$G = \frac{F \cdot d}{(m 1) (m 2)}$ $G=(F*d)/((m1)(m2))$

$F = \frac{G (m 1) (m 2)}{d}$ $F=(G(m1)(m2))/d$

$F \cdot d = G (m 1) (m 2)$ $F*d=G(m1)(m2)$

$\frac{F \cdot d}{(m 1) (m 2)} = G$ $(F*d)/((m1)(m2))=G$

Answer 2 · 2018-05-02T16:41:55

$G = \frac{F d}{m_{1} m_{2}}$ $G = (Fd)/(m_1m_2)$

$F = \frac{G m_{1} m_{2}}{d}$ $F = (Gm_1m_2)/d$

Making $G$ $G$ the subject of formula;

$\frac{F}{1} = \frac{G m_{1} m_{2}}{d}$ $F/1 = (Gm_1m_2)/d$

Cross multiplying..

$F \times d = G m_{1} m_{2} \times 1$ $F xx d = Gm_1m_2 xx 1$

$F d = G m_{1} m_{2}$ $Fd = Gm_1m_2$

Divide both sides by $m_{1} m_{2}$ $m_1m_2$

$\frac{F d}{m_{1} m_{2}} = \frac{G m_{1} m_{2}}{m_{1} m_{2}}$ $(Fd)/(m_1m_2) = (Gm_1m_2)/(m_1m_2)$

$(Fd)/(m_1m_2) = (Gcancel(m_1m_2))/cancel(m_1m_2)$

$(Fd)/(m_1m_2) = G$

Given F = (Gm_1m_2)/dF=Gm1m2dF = (Gm_1m_2)/d, how do you solve for GGG?