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Sinx. Cosx=1/2?

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F. Javier B. · mason m

May 2, 2018

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Explanation:

Remember that $2 sin x cos x = sin 2 x$ $2sinxcosx=sin2x$

In our equation $sin x cos x = \frac{1}{2}$ $sinxcosx=1/2$ multiply by 2 both sides

$2 sin x cos x = 1$ $2sinxcosx=1$ , then $sin 2 x = 1$ $sin2x=1$

Thus we have $2x=90º=pi/2+2kpi$ because sinx is periodic

Finally we have $x=pi/4+kpi$ where $k$ is an integer

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