How do you simplify $(-8)^(-1/3)$ ?

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Answer 1 · 2018-05-03T09:59:08

$-1/2$

$a^-n=1/a^n " "$ [this is a proved result]

So,

$-8^(-1/3)=(-1/8)^(1/3)$

$(-1/8)^(1/3)= root(3)(-1/8)=-1/2$

Answer 2 · 2018-05-03T10:01:39

$(-8)^(-1/3)=-1/2$

$(-8)^(-1/3)=^"-3"sqrt(-8)$
$=1/(^"3"sqrt(-8))$
$=-1/2$
\0/ here's our answer !

How do you simplify (-8)^(-1/3)(-8)^(-1/3)?