How do you write an equation in standard form with integer coefficients for the line with slope 17/12 going through the point (-5,-3)?

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How do you write an equation in standard form with integer coefficients for the line with slope 17/12 going through the point (-5,-3)?

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Answer 1 · 2018-05-03T15:14:44

$17 x - 12 y = - 49$ $17x-12y=-49$

Explanation:

The equation is like that:
$y = m x + b$ $y=mx+b$
$m$ $m$ is the slope which equals to $\frac{17}{12}$ $17/12$
$x = - 5$ $x=-5$
$y = - 3$ $y=-3$
$b$ $b$ is the intercept.

So
$- 3 = \frac{17}{12} \cdot (- 5) + b$ $-3=17/12*(-5)+b$
$- 3 = - \frac{85}{12} + b$ $-3=-85/12+b$
$- 3 + \frac{85}{12} = b$ $-3+85/12=b$
$- \frac{36}{12} + \frac{85}{12} = b$ $-36/12+85/12=b$
$\frac{49}{12} = b$ $49/12=b$

An equation in standard form:
$y = \frac{17}{12} x + \frac{49}{12}$ $y=17/12x+49/12$
$y \cdot 12 = \frac{17}{12} \cdot 12 + \frac{49}{12} \cdot 12$ $y*12=17/12*12+49/12*12$
$12 y = 17 x + 49$ $12y=17x+49$
$17 x - 12 y = - 49$ $17x-12y=-49$

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How do you write an equation in standard form with integer coefficients for the line with slope 17/12 going through the point (-5,-3)?

1 Answer

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