How do you find the product of $(y + 8) (y + 6)$ ?

Question

4013 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-03T15:44:48

$y^2 + 14x +48$

To multiply the binomials $(y+8)(y+6)$
we would incorporate the FOIL

F = Firsts
O = Outers
I = Inners
L = Lasts

Multiplying the Firsts $y*y$
Multiplying the Outers $+6*y$ and $+8*y$
Multiplying the Lasts $(+8)*(+6)$

enter image source here

We get
$y^2 + 6y + 8y + 48$

Now add like terms

$y^2 +14x + 48$

How do you find the product of (y + 8) (y + 6) (y + 8) (y + 6) ?