What is #\int \frac { 16x - 15y } { 32} - 6 dx#?

1 Answer
Daniel
May 4, 2018

#x^2/4-(15xy)/32-6x+C#

Explanation:

#int_##(16x-15y)/(32)-6 dx#

#1/32##int_##(16x-15y) dx##-6##int_##1 dx#

#1/2##int_##x dx##+((15y)/32-6)##int_##1 dx#

#x^2/4+(-(15y)/32-6)##int_##1 dx#

#x^2/4+(-(15y)/32-6)x+C#

#=x^2/4-(15xy)/32-6x+C#

Related questions
Impact of this question
1247 views around the world
You can reuse this answer
Creative Commons License