How do you simplify #(6+ 4x + 8x ^ { 2} + 3x ^ { 3} ) + ( 4- 4x + 8x ^ { 2} - 3x ^ { 3} )#?

Question

1540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-04T18:02:25

#10+16x^2#

#(6+ 4x + 8x ^ { 2} + 3x ^ { 3} ) + ( 4- 4x + 8x ^ { 2} - 3x ^ { 3} )#
#=(6+4)+(4x-4x)+(8x^2+8x^2)+(-3x^3+3x^3)#
#=10+16x^2#

Answer 2 · 2018-05-04T18:05:04

Just add quantities with the same variables

With or without the parenthesis, just add (or subtract) the quantities given.

#6+cancel(4x)+8x^2+cancel(3x^3)+4-cancel(4x)+8x^2-cancel(3x^3)#

#6+8x^2+4+8x^2#

#10+16x^2#

The exponent on the variables will not change because you are only changing the number they will be multiplied by.