What is the equation of a circle with center (6, –4) and radius 6?

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Answer 1 · 2018-05-05T00:48:49

$(x-6)^2 + (x-(-4))^2 = 6$

Used Formula

$(x-h)^2 + (y-k)^2 = r$

where $r$ =radius

In your case $h=6$ , $k=-4$ and $r= 6$

Answer 2 · 2018-05-05T00:50:49

$(x-6)^2+(y+4)^2=36$

Equation of a circle: $(x-h)^2+(y-k)^2=r^2 rarr (h, k)$ is the center of the circle and $r$ is the radius

Plug $6$ in for $h$ , $-4$ in for $k$ , and $6$ in for $r$ :

$(x-6)^2+(y-(-4))^2=6^2$

$(x-6)^2+(y+4)^2=36$