What is the equation of a circle with center (6, –4) and radius 6?

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Answer 1 · 2018-05-05T00:48:49

#(x-6)^2 + (x-(-4))^2 = 6#

Used Formula

#(x-h)^2 + (y-k)^2 = r#

where #r#=radius

In your case #h=6#, #k=-4# and #r= 6#

Answer 2 · 2018-05-05T00:50:49

#(x-6)^2+(y+4)^2=36#

Equation of a circle: #(x-h)^2+(y-k)^2=r^2 rarr (h, k)# is the center of the circle and #r# is the radius

Plug #6# in for #h#, #-4# in for #k#, and #6# in for #r#:

#(x-6)^2+(y-(-4))^2=6^2#

#(x-6)^2+(y+4)^2=36#