How do you solve $4 x - 11 = 5 x - 19$ $4x - 11= 5x - 19$ ?

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Answer 1 · 2018-05-05T01:55:34

$x = 8$ $x=8$

In order to solve $4 x - 11 = 5 x - 19$ $4x-11=5x-19$

Begin by using the additive inverse to combine like terms on the opposite sides of the equal sign

$cancel(4x)-11 cancel (-4x)=5x-19 -4x$

$-11 = x-19$

$-11 + 19 = xcancel(-19) cancel(+19)$

$8=x$

How do you solve 4x - 11= 5x - 194x−11=5x−194x - 11= 5x - 19?