How do you simplify #sqrt(169x^4y^7)#?

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Answer 1 · 2018-05-05T03:38:30

#13x^2y^(7/2)#

Square root is essentially raising what's in the radical to the 1/2 power, so:

#(169x^4y^7)^(1/2)#

So now, just simplify:

#169^(1/2)#=13

#x^(4*1/2=2)=x^2#

#y^(7*1/2=7/2)=y^(7/2)#

And now put it all together....

#13x^2y^(7/2)#

Hope this helped!!!