How do you simplify $\sqrt{169 x^{4} y^{7}}$ $sqrt(169x^4y^7)$ ?

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Answer 1 · 2018-05-05T03:38:30

$13 x^{2} y^{\frac{7}{2}}$ $13x^2y^(7/2)$

Square root is essentially raising what's in the radical to the 1/2 power, so:

${(169 x^{4} y^{7})}^{\frac{1}{2}}$ $(169x^4y^7)^(1/2)$

So now, just simplify:

$169^{\frac{1}{2}}$ $169^(1/2)$ =13

$x^{4 \cdot \frac{1}{2} = 2} = x^{2}$ $x^(4*1/2=2)=x^2$

$y^{7 \cdot \frac{1}{2} = \frac{7}{2}} = y^{\frac{7}{2}}$ $y^(7*1/2=7/2)=y^(7/2)$

And now put it all together....

$13 x^{2} y^{\frac{7}{2}}$ $13x^2y^(7/2)$

Hope this helped!!!

How do you simplify √169x4y7sqrt(169x^4y^7)?