$A × B^x = C/D^x-2$ solve for x in log form ?

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Answer 1 · 2018-05-05T06:35:43

$x= (-log(a)-log(2)+log(c))/(log(b)+log(d))$

first, we need to log both sides.

$log(a) + xlog(b) = log(c)-xlog(d) - log(2)$

isolate x

$xlog(b)+xlog(d)=-log(a)-log(2)+log(c)$
$x(log(b)+log(d))=-log(a)=log(2)+log(c)$

$x = (-log(a)-log(2)+log(c))/(log(b)+log(d))$

A × B^x = C/D^x-2A × B^x = C/D^x-2 solve for x in log form ?