How do you multiply #sqrt6 * sqrt6#?

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Answer 1 · 2018-05-05T18:14:21

#6#

we know:

#sqrta xx sqrtb=sqrt(ab)#

#therefore# #sqrt6 xx sqrt6=sqrt36#

simplifying (if possible):

#sqrt36 =6#

Answer 2 · 2018-05-06T02:01:49

Given: #sqrt(6)xxsqrt6#

#=(sqrt6)^2#

#=6#