If #x^2# + #y^2# = #3xy#, show that #log (x-y) = 1/2(log x + log y) How do you solve this?
1 Answer
May 6, 2018
Solve by Condensing the Right Side and using the Properties of Logs.
Explanation:
Condense Right Side
Coefficient becomes the Power of
Eliminate
Square both sides
Add