How to calculate average pressure as volume changes via intergration?
A quantity of gas expands according to the law pv^0.9=300, where v m^3 is the volume of the gas and p N/m^2 is the pressure
a) what is the average pressure as the volume changes from 1/2 m^3 to 1 m^3?
A quantity of gas expands according to the law pv^0.9=300, where v m^3 is the volume of the gas and p N/m^2 is the pressure
a) what is the average pressure as the volume changes from 1/2 m^3 to 1 m^3?
1 Answer
May 6, 2018
Explanation:
The idea is the simple geometric one that:
You would expect pressure to drop over the expansion, so reality check:
-
#p_1 approx 560 " Pa"# -
#p_2 = 300 " Pa" # -
#p_2 lt p_("ave") lt p_1# , which is expected