Question

How do you solve and write the following in interval notation: `x^2-2x+4>0`?

Answer 1

inequality always true.

Explanation:

`f(x) = x^2 - 2x + 4 > 0`
`D = d^2 = b^2 - 4ac = 4 - 16 = - 12 < 0`
Because D < 0, there are no real roots. The graph is an upward parabola (a > 0). The graph stays completely above the x-axis.
The inequality is always true.