How do you solve #7x-2y=8# and #5x+2y=4# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer G_Ozdilek May 7, 2018 Find #2y# in the first and put the value in the second equation Explanation: #7x-8 = 2y# after arranging the first original equation. Put this into the second #5x + 2y = 4# #5x + 7x - 8 = 4# #12x = 4+8# #x = 12/12 = 1# Now find y. #2y=7x-8# #2y = 7-8# #2y = -1# #y=-1/2# Your answer is #x=1# and #y=-1/2# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 3065 views around the world You can reuse this answer Creative Commons License