The length of a rectangular tabletop is 18 inches more than the width. The perimeter is 244 inches. What is the width of the tabletop?

2 Answers
May 7, 2018

52 inches.

Explanation:

We know that the perimeter of a rectangle is equivalent to twice the width plus twice the length.

P = 2w+2lP=2w+2l

Since the length is 18 more then the width, we can rewrite ll as (w+18).(w+18). Plug in that in place of ll and plug in 244 for the perimeter, and you can solve for the width.

244 = 2w + 2(w+18)244=2w+2(w+18)

Distribute:

244 = 2w + 2w+36244=2w+2w+36

Combine like terms:

244 = 4w + 36244=4w+36

Subtract 36 from each side:

208 = 4w208=4w

Divide each side by 4:

52 = w52=w

May 7, 2018

52" "52 inches

Explanation:

for a rectangle

l=l=length, w=w=width

perimeter" "P=2(l+w) P=2(l+w)

we have " "l=w+18 l=w+18

:.244=2(w+18+w)

122=2w+18

w=(122-18)/2=52" inches"