Question

What is the area under `f(x)=5` in `x in[0,2]`?

Answer 1

`10m^2`

Explanation:

`Area_((OABΓ))=x*y=2*5=10m^2`

or

`int_0^2` `5dx` `=` `5int_0^2` `(x)'dx` `=`

`5[x]_0^2=5(2-0)=5*2=10m^2`

(Used the greek letter `Γ` for `O(0,0`))