How do you foil $4 (3 x + 1) (x - 2)$ $4 (3x+1) (x-2)$ ?

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Answer 1 · 2018-05-08T17:34:03

$12 x^{2} - 20 x - 8$ $12x^2-20x-8$

First, distribute the $4$ $4$ to the $(3 x + 1)$ $(3x+1)$ :
$4 \cdot 3 x = 12 x$ $4*3x=12x$
$4 \cdot 1 = 4$ $4*1=4$

Then, use FOIL to multiply $(12 x + 4) (x - 2)$ $(12x+4)(x-2)$ :

First: $12 x \cdot x = 12 x^{2}$ $12x*x = 12x^2$

Outer: $12 x \cdot - 2 = - 24 x$ $12x*-2 = -24x$

Inner: $4 \cdot x = 4 x$ $4*x = 4x$

Last: $4 \cdot - 2 = - 8$ $4*-2 = -8$

Your expression is now:

$12 x^{2} - 24 x + 4 x - 8$ $12x^2-24x+4x-8$

and you can combine $- 24 x + 4 x$ $-24x+4x$ , as they are like terms, to get a final answer of:

$12 x^{2} - 20 x - 8$ $12x^2-20x-8$

How do you foil 4 (3x+1) (x-2)4(3x+1)(x−2)4 (3x+1) (x-2)?