How do you write the slope intercept form of the line #13x-11y=-12#?

2 Answers
May 8, 2018

#y=13/11x+12/11#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"rearrange "13x-11y=-12" into this form"#

#"subtract "13x" from both sides"#

#cancel(13x)cancel(-13x)-11y=-13x-12#

#rArr-11y=-13x-12#

#"multiply through by "-1#

#11y=13x+12#

#"divide all terms by 11"#

#rArry=13/11x+12/11larrcolor(red)"in slope-intercept form"#

May 8, 2018

#y=13/11x+12/11#

Explanation:

The first step is to re-arrange the equation such that #y# and its coefficients are alone:

#cancel(13x)-11ycolor(red)(cancel(-13x))=-12color(red)(-13x)#

#-11y=-13x-12#

Next, divide through by #y#'s coefficient, and you will have slope-intercept form:

#(cancel(-11)y)/color(red)(cancel(-11))=(cancel(-)13x)/color(red)(cancel(-)11)+(cancel(-)12)/color(red)(cancel(-)11)#

#color(green)(y=13/11x+12/11)#