Solve for #x#? #e^(2x)-5=ln(x)+7# Please and thank you!!
1 Answer
Explanation:
I would solve this graphically, as algerbraically seems rather advanced. I would draw two graphs,
the values of x that solve the equation, have to be on both graphs, i.e. must be where the graphs cross each other.
We find that there are two solutions, A=(0, -4) and E=(1.25, 7.22)
Now, ln(0) is undefined, but we see that
x=0 inserted in g:
The other value is