What is the cubed root of 8?

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Answer 1 · 2018-05-09T20:43:06

$\sqrt[3]{8} = 2$ $root(3)8=2$

The cube root of $x$ $x$ (denoted by $\sqrt[3]{x}$ $root(3)x$ ) is a number that you multiply by itself three times to get $x$ $x$ .

The cube root of $8$ $8$ is $2$ $2$ , because:

$2 \cdot 2 \cdot 2 = 4 \cdot 2 = 8$ $2*2*2=4*2=color(red)(8)$

You can also use exponents:

$2^{3} = 2^{2} \cdot 2^{1} = 4 \cdot 2 = 8$ $2^3=2^2*2^1=4*2=color(red)(8)$

Answer 2 · 2018-05-09T20:44:56

$\sqrt[3]{8} = {(8)}^{\frac{1}{3}} = {(2^{3})}^{\frac{1}{3}} = 2$ $root(3)8= (8)^(1/3)=(2^3)^(1/3)=2$

show that $8 = 2^{3}$ $8=2^3$

cubic root of x equals $x^{\frac{1}{3}}$ $x^(1/3)$

cubic root of 8 equals ${(8)}^{\frac{1}{3}} = {(2^{3})}^{\frac{1}{3}} = 2$ $(8)^(1/3)=(2^3)^(1/3)=2$

note that

${(x^{n})}^{m} = x^{n \cdot m}$ $(x^n)^m=x^(n*m)$