How do you find the derivative of $ln((sin^2)x)$ ?

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Answer 1 · 2018-05-09T20:51:22

$d/(dx) ln(sin^2(x)) =2 cot(x)$

$d/(dx) ln(sin^2(x)) = (d/(dx)sin^2(x))/(sin^2(x))=(2 sin(x) cos(x))/(sin^2(x))=(2 cos(x))/(sin(x))$

How do you find the derivative of ln((sin^2)x) ln((sin^2)x) ?