How many moles of $"H"_2"SO"_4$ are present in $"0.500 L"$ of a $"0.150-M"$ $"H"_2"SO"_4$ solution?

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Answer 1 · 2018-05-09T21:04:03

$"0.0750 moles H"_2"SO"_4$

$"Molarity"$ $= "Moles"/"Liter"$

Using this, we can fill in several of these values since they are given. This gives us the equation:

$0.150 = ("Moles")/0.500$

By multiplying both sides by $0.500$ , we find

$"0.150 mol/L" * "0.500 L" = "Moles"$

or simplified

$"0.0750 mol = Moles"$

How many moles of "H"_2"SO"_4"H"_2"SO"_4 are present in "0.500 L""0.500 L" of a "0.150-M""0.150-M" "H"_2"SO"_4"H"_2"SO"_4 solution?