How many moles of #"H"_2"SO"_4# are present in #"0.500 L"# of a #"0.150-M"# #"H"_2"SO"_4# solution?

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Answer 1 · 2018-05-09T21:04:03

#"0.0750 moles H"_2"SO"_4#

#"Molarity"# #= "Moles"/"Liter"#

Using this, we can fill in several of these values since they are given. This gives us the equation:

#0.150 = ("Moles")/0.500#

By multiplying both sides by #0.500#, we find

#"0.150 mol/L" * "0.500 L" = "Moles"#

or simplified

#"0.0750 mol = Moles"#