How do you solve $\frac{1}{5} q = 9 - \frac{2}{5} 9$ $\frac{1}{5} q = 9- \frac{2}{5} 9$ ?

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Answer 1 · 2018-05-10T07:04:01

By some arrangement

$\frac{q}{5} = 9 - \frac{2}{5} 9$ $q/5 = 9 - 2/5 9$

$\frac{q}{5} = 9 - \frac{47}{5}$ $q/5 = 9 - 47/5$

$\frac{q}{9} = \frac{45}{5} - \frac{47}{5}$ $q/9 = 45/5 - 47/5$

$\frac{q}{9} = - \frac{2}{5}$ $q/9 = -2/5$

$q = - \frac{18}{5}$ $q = -18/5$

$q = - 3 \frac{3}{5}$ $q= -3 3/5$

How do you solve 15q=9−259\frac{1}{5} q = 9- \frac{2}{5} 9?