Graph the quadratic equation, labeling the vertex and the y-intercept. y=x^2-6x-4 ?

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Answer 1 · 2018-05-10T13:15:08

Please see the explanation.

#y=x^2-6x-4#

To find the #y# intercept set #x# to zero:

#y=0-0-4=># #y=-4#

Complete the square to convert into vertex form:

#y=(x^2-6x+9)-4-9#

#y=(x-3)^2-13#

The vertex is at:#(3, -13)#

Graph the quadratic​ equation, labeling the vertex and the​ y-intercept. y=x^2-6x-4 ?