Graph the quadratic equation, labeling the vertex and the y-intercept. y=x^2-6x-4 ?

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Answer 1 · 2018-05-10T13:15:08

Please see the explanation.

$y = x^{2} - 6 x - 4$ $y=x^2-6x-4$

To find the $y$ $y$ intercept set $x$ $x$ to zero:

$y = 0 - 0 - 4 \Rightarrow$ $y=0-0-4=>$ $y = - 4$ $y=-4$

Complete the square to convert into vertex form:

$y = (x^{2} - 6 x + 9) - 4 - 9$ $y=(x^2-6x+9)-4-9$

$y = {(x - 3)}^{2} - 13$ $y=(x-3)^2-13$

The vertex is at: $(3, - 13)$ $(3, -13)$

Graph the quadratic​ equation, labeling the vertex and the​ y-intercept. y=x^2-6x-4 ?