How do you solve $2 x = - 6 x^{2}$ $2x=-6x^2$ ?

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How do you solve $2 x = - 6 x^{2}$ $2x=-6x^2$ ?

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Answer 1 · 2018-05-10T19:28:10

$x$ $x$ = $0$ $0$ or $- \frac{1}{3}$ $-1/3$

Explanation:

$2 x$ $2x$ = $- 6 x^{2}$ $-6x^2$
$6 x^{2} + 2 x = 0$ $6x^2 + 2x = 0$
$2 x (3 x + 1) = 0$ $2x( 3x + 1) = 0$
$2 x = 0$ $2x = 0$ or $(3 x + 1) = 0$ $(3x + 1) = 0$
$x$ $x$ = $0$ $0$ or $- \frac{1}{3}$ $-1/3$

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How do you solve $2 x = - 6 x^{2}$ $2x=-6x^2$ ?

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