Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Write the equation of a circle that has a center of ( 2,-6) and goes through (8,4)?

1 Answer

May 10, 2018

Equation: ${(x - 2)}^{2} + {(y + 6)}^{2} = {(11.661)}^{2}$ $(x-2)^2 + (y+6)^2 = (11.661)^2$

Explanation:

Basic Circle Equation:
${(x - k)}^{2} + {(y - h)}^{2} = r^{2}$ $(x-k)^2 + (y-h)^2 = r^2$
Where $(k, h)$ $(k,h)$ is the center.

Therefore,
$r = \sqrt{{(8 - 2)}^{2} + {(4 + 6)}^{2}}$ $r = sqrt((8-2)^2 + (4 + 6)^2)$
$r = 11.661$ $r = 11.661$

Equation: ${(x - 2)}^{2} + {(y + 6)}^{2} = {(11.661)}^{2}$ $(x-2)^2 + (y+6)^2 = (11.661)^2$

Related questions

Impact of this question

888 views around the world

You can reuse this answer
Creative Commons License