How do I find the derivative of #ln(ln(2x))#?

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Answer 1 · 2018-05-11T11:29:13

#dy/dx=1/(xln(2x))#

#y=ln(ln(2x))#

#dy/dx=d/dx[ln(ln(2x))]#

#dy/dx=(d/dx[ln(2x)])/ln(2x)#

#dy/dx=(((d/dx[2x])/(2x)))/ln(2x)#

#dy/dx=((2/(2x)))/ln(2x)#

#dy/dx=((1/x))/ln(2x)#

#dy/dx=1/(xln(2x))#