Question

What is the derivative of `ln(sin^2x)`?

Answer 1

Use chain rule
`f(x)=h(g(x))`
`f'(x)=h'(g(x)) g'(x)`

Explanation:

`ln(sin^2(x))`

`(ln(sin^2(x)))'=`
`=1/(sin^2(x))*(sin^2(x))'=`

`=1/(sin^2(x))2*(sin(x))*(sin(x))'=`

`=2/(sin(x))*(cos(x))=2/tan(x)=2 cot(x)`