Evaluate log2^(1÷8)?

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Answer 1 · 2018-05-12T05:08:32

-.60205...

${log 2}^{\frac{1}{8}}$ $log2^(1/8)$ intends that it is a common log, making it the same as ${log}_{10} 2^{\frac{1}{8}}$ $log_(10)2^(1/8)$

First, let's simplify the 2.

$2^{\frac{1}{8}}$ $2^(1/8)$ = $\frac{1}{4}$ $1/4$

So, ${log}_{10} (\frac{1}{4})$ $log_(10)(1/4)$

This can also be written in exponential form, yielding:

$10^{x}$ $10^x$ = $\frac{1}{4}$ $1/4$

Either way, the answer comes out to be roughly -.60205...