How do you solve $\frac{5 x + 1}{x - 1} = \frac{15 x - 17}{3 x - 7}$ $\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}$ ?

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How do you solve $\frac{5 x + 1}{x - 1} = \frac{15 x - 17}{3 x - 7}$ $\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}$ ?

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Answer 1 · 2018-05-12T06:57:33

no real solutions for x

Explanation:

$\frac{5 x + 1}{x - 1} = \frac{15 x - 17}{3 x - 7}$ $(5x+1)/(x-1)=(15x-17)/(3x-7)$

$\frac{5 x + 1}{x - 1} \times (x - 1) (3 x - 7) = \frac{15 x - 17}{3 x - 7} \times (x - 1) (3 x - 7)$ $(5x+1)/(x-1)xx(x-1)(3x-7)=(15x-17)/(3x-7)xx(x-1)(3x-7)$

$(5 x + 1) \times (3 x - 7) = (15 x - 17) \times (3 x - 7)$ $(5x+1)xx(3x-7)=(15x-17)xx(3x-7)$

$5 x (3 x - 7) + 1 (3 x - 7) = 15 x (3 x - 7) - 17 (3 x - 7)$ $5x(3x-7)+1(3x-7)=15x(3x-7)-17(3x-7)$

$15 x^{2} - 35 x + 3 x - 7 = 45 x^{2} - 105 - 51 x + 119$ $15x^2-35x+3x-7=45x^2-105-51x+119$

$15 x^{2} - 32 x - 7 = 45 x^{2} - 51 x + 14$ $15x^2-32x-7=45x^2-51x+14$

$0 = (45 - 15) x^{2} + (- 51 + 32) x + (14 + 7)$ $0=(45-15)x^2+(-51+32)x+(14+7)$

$0 = 30 x^{2} - 19 x + 21$ $0=30x^2-19x+21$

find discriminant:
$Delta=(-19)^2-4xx30xx21=-2159$
$Delta<0$
$:.$ no real solutions for x

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How do you solve $\frac{5 x + 1}{x - 1} = \frac{15 x - 17}{3 x - 7}$ $\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}$ ?

1 Answer

Explanation:

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How do you solve \frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}5x+1x−1=15x−173x−7\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}?

1 Answer

Explanation:

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How do you solve $\frac{5 x + 1}{x - 1} = \frac{15 x - 17}{3 x - 7}$ $\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}$ ?