How do you solve #4x+8=32#?

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Answer 1 · 2018-05-12T07:04:48

#x=6#

#4x+8=32#

Isolate for #x#. Start by subtracting #8# from both sides of the equation.

#4x+8 color(red)(-8) = 32 color(red)(-8)#

#color(green)(4x=24)#

Divide both sides of the equation by #4#.

#color(green)(4x)/color(blue)(4)=color(green)(24)/color(blue)(4)#

#color(purple)(x=6)#