A balloon is filled with 4.57 liters of air at room temperature(23.3 deg C). Liquid nitrogen is poured over the balloon until the gas is at a temperature of -197 degrees C. What volume with the gas have inside the balloon?

The pressure on the inside of the balloon will remain constant throughout the experiment

1 Answer
Rita
May 13, 2018

#V_2# = #1.22L#

Explanation:

So refer to the Charle's Law equation

#(V_1)/(T_1)# = #(V_2)/(T_2)#

  • we know it's this equation because of constant pressure

We have our first volume #(V_1)# which is #4.57 L#
Our first temperature #(T_1)# which is #23.3^@C#
And our second temperature #(T_2)# which is #-197^@C#

Our unknown is the second volume #(V_2)#

Before we plug our values into the equation, we need to convert the temperature into Kelvin #(K)#

We can do this by taking the #C^@# and adding #273#

#T_1#: #23.3^@C# + #273# = #296.3K#

#T_2#: #-197^@C# + #273# = #76K#

Now we can plug our values into the equation

#(4.57 L)/(296.3K)#=#(V_2)/(76K)#

We need to isolate #V_2# so we multiply both sides by #(76K)/(1)#

#(76cancelK)/(1)# x #(4.57 L)/(296.3cancelK)#=#(V_2)/(cancel(76K))# x #(cancel(76K))/(1)#

  • The Kelvin #(K)# cancel out, leaving Liters #(L)#

After you multiply #76# by #4.57L# then divide by #296.3#, your answer should be

#V_2# = #1.22L#

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