Question

The weather in Nome is -15.1 degrees C.If Jane is on her morning jog alone the streets of Nome and fully exhales 4.98 L of air from her lungs, what will the new volume of this air be? The air while in Jane's lungs is at her body temperature, 38 degrees C.

Answer 1

Recall the relationship between volume and temperature of an ideal gas,

`PV = nRT`

`=> V_1/T_1 = (nR)/P = V_2/T_2`

`=> V_1/T_1 = V_2/T_2`

Given,

`V_1 = 4.98"L"`

`T_1 = -15.1°"C" = 258.05"K"`

`T_2 = 38°"C" = 311.15"K"`

Hence, Jane would have respired,

`=> V_2 = (V_1T_2)/T_1 approx 6.00"L"`

of air into her lungs.