How do you use cross products to solve #2/t=5/(t-6)#?
2 Answers
May 14, 2018
Explanation:
Cross multiply the denominator with numerator like:
Add
May 14, 2018
Explanation:
#"using the method of "color(blue)"cross-products"#
#•color(white)(x)a/b=c/drArrbc=ad#
#rArr5t=2(t-6)#
#rArr5t=2t-12#
#"subtract "2t" from both sides"#
#5t-2t=cancel(2t)cancel(-2t)-12#
#rArr3t=-12#
#"divide both sides by 3"#
#(cancel(3) t)/cancel(3)=(-12)/3#
#rArrt=-4#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left "=2/(-4)=-1/2#
#"right "=5/(-4-6)=5/(-10)=-1/2#
#rArrt=-4" is the solution"#