Question

Calculate the tensile stress in a nylon fishing line of diameter 0.36 mm which a fish is pulling with a force of 20 N?

Answer 1

`5 GPa`

Explanation:

`Stress = F/A`

Find Area of the nylon fishing line using `A=pir^2` and half the diameter to get the radius and make sure you convert mm into m (`*10^-3`):

`A=pi*((0.36*10^-3)/2)^2`
`A= 1.01787602*10^-7 m^2`

Substitute this value into stress equation:

`Stress = (1.01787602*10^-7)/20`
`Stress = 5*10^-9 Pa`
`Stress = 5 GPa`