How do you find the slope of a line perpendicular to the line to the line through the points (7,-10) and (6,-1)?

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Answer 1 · 2018-05-14T17:54:28

The perpendicular slope would be $m = \frac{1}{9}$ $m=1/9$

Let's begin by finding the slope of the line through the two points, $(7, - 10)$ $(7,-10)$ and $(6, - 1)$ $(6,-1)$

Slope is The change in $y$ $y$ rise over the change in $x$ $x$ run.

$m = (Deltay)/(Deltax)$

and can be found using the equation

$m=(y_2-y_1)/(x_2-x_1)$

For the points given the coordinates are

$x_1 = 7$
$y_1 = -10$
$x_2 = 6$
$y_2=-1$

Plug in the values and solve for slope

$m=(-1 -(-10))/(6-7)$

$m = 9/-1$

$m =-9$

The line perpendicular to this line would have a slope that is the inverse of this line. Both in sign and reciprocal.

#m - 1/9