How do you multiply $(x^{2} - 5 x) (5 x - 25)$ $(x ^ { 2} - 5x ) ( 5x - 25)$ ?

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How do you multiply $(x^{2} - 5 x) (5 x - 25)$ $(x ^ { 2} - 5x ) ( 5x - 25)$ ?

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Answer 1 · 2018-05-14T19:09:31

$5 x^{3}$ $5x^3$ - $50 x^{2}$ $50x^2$ + $125 x$ $125x$

Explanation:

F.O.I.L.

First, Outer, Inner, Last: order of terms to multiplied

First terms:
(x^2 - 5x)(5x - 25)

$5 x$ $5x$ * $x^{2}$ $x^2$ = $5 x^{3}$ $5x^3$

Outer terms:
(x^2 - 5x)(5x - 25)

$x^{2}$ $x^2$ * $- 25$ $-25$ = $- 25 x^{2}$ $-25x^2$

Inner terms:
( $x^{2}$ $x^2$ - 5x)(5x - 25)

$- 5 x \cdot 5 x$ $-5x * 5x$ = $- 25 x^{2}$ $-25x^2$

Last terms:
( $x^{2}$ $x^2$ - 5x)(5x - 25)

$- 5 x \cdot - 25$ $-5x * -25$ = $125 x$ $125x$ because two negatives make a positive.

Add all your terms together:

$5 x^{3}$ $5x^3$ - $25 x^{2}$ $25x^2$ $- 25 x^{2}$ $-25x^2$ + $125 x$ $125x$

Combine like terms.

$5 x^{3}$ $5x^3$ - $50 x^{2}$ $50x^2$ + $125 x$ $125x$

Answer 2 · 2018-05-14T19:18:46

Through distribution

Explanation:

First take $x^{2}$ $x^2$ * 5x, then $x^{2}$ $x^2$ * -25, after distributing the $x^{2}$ $x^2$ do the same with the -5x in the first parenthesis. After getting your solutions ( $5 x^{3}$ $5x^3$ + $25 x^{2}$ $25x^2$ - $10 x^{2} + 125 x$ $10x^2+125x$ ) you can simplify. Adding the $25 x^{2}$ $25x^2$ and the $10 x^{2}$ $10x^2$ getting $35 x^{2}$ $35x^2$ .

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How do you multiply $(x^{2} - 5 x) (5 x - 25)$ $(x ^ { 2} - 5x ) ( 5x - 25)$ ?

2 Answers

Explanation:

Explanation:

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How do you multiply (x2−5x)(5x−25)(x ^ { 2} - 5x ) ( 5x - 25)?

2 Answers

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How do you multiply $(x^{2} - 5 x) (5 x - 25)$ $(x ^ { 2} - 5x ) ( 5x - 25)$ ?