How do you solve $- 2 \leq x + 1 < 14$ $-2\leq x + 1< 14$ ?

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Answer 1 · 2018-05-14T23:09:55

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$- 2 \leq x + 1 < 14$ $-2 <= x + 1 <14$

The only thing we can do here is by adding $- 1$ $-1$ to all parts of the inequality

$- 2 - 1 \leq x + 1 - 1 < 14 - 1$ $-2 - 1 <= x + 1 - 1 < 14-1$

$- 3 \leq x < 13$ $-3 <=x <13$

How do you solve -2\leq x + 1< 14−2≤x+1<14-2\leq x + 1< 14?