How do you solve $\frac{x - 2}{5} = \frac{2 x - 1}{11}$ $\frac { x - 2} { 5} = \frac { 2x - 1} { 11}$ ?

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Answer 1 · 2018-05-15T02:07:43

$x = 17$ $x = 17$

Multiply the left-hand numerator $(x - 2)$ $(x -2)$ by $11$ $11$ . Multiply the right-hand numerator $(2 x - 1)$ $(2x-1)$ by $5$ $5$ .

So

$11 x - 22 = 10 x - 5$ $11x-22=10x -5$

$11 x - 22 - 10 x = 10 x - 5 - 10 x$ $11x-22-10x=10x -5-10x$

$x - 22 = - 5$ $x - 22 = -5$

So

$x - 22 + 22 = - 5 + 22$ $x - 22+22 = -5+22$

$x = 17$ $x= 17$

You can substitute $17$ $17$ in to original equation to check:

$\frac{17 - 2}{5} = \frac{17 \times 2 - 1}{11}$ $(17-2)/5 =(17xx2-1)/11$

$3 = 3$ $3=3$

How do you solve x−25=2x−111\frac { x - 2} { 5} = \frac { 2x - 1} { 11}?