How do you solve $-6(x-4)>2x+8$ ?

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Answer 1 · 2018-05-15T09:46:21

$x<2$

Simply the equation further by opening the brackets first.

$-6(x-4) > 2x+8$

$-6x -(4xx(-6)) > 2x + 8$

$-6x-(-24) > 2x +8$

$-6x+24 > 2x +8$

Subtract $24$ both sides:

$-6x+24-24 > 2x+8-24$
$-6x > 2x-16$

Subtract $2x$ both sides:

$-6x-2x > -16$
$-8x > -16$

When dividing or multiplying by negative number, the inequality sign changes from $>$ to $<$ . This is very important to remember.

$x < (-16)/-8$

$x<2$

Check the answer:
Let $x = 1$
$-6(-1-4) > 2(1)+8$
$-6xx(-5) > 2+8$
$30 > 10$

How do you solve -6(x-4)>2x+8-6(x-4)>2x+8?