How do you factor $x^{2} + 4 x + 1$ $x^2+4x+1$ ?

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Answer 1 · 2018-05-15T12:16:13

Either ${(x + 1)}^{2} + 2 x$ $(x+1)^2+2x$ or ${(x + 2)}^{2} - 3$ $(x+2)^2-3$

I really don't think I need an explanation for this. What I can say is that it is not a perfect square.

How do you factor x^2+4x+1x2+4x+1x^2+4x+1?