What is the perimeter of a triangle with corners at #(1 ,5 )#, #(6 ,3 )#, and #(4 ,1 )#?

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Answer 1 · 2018-05-15T19:37:35

#13.21# to 2 decimal points. (in surd form: #sqrt{29}+5+2sqrt{2}# )

There are many ways to approach this.

Let
A = #(1,5)#
B = #(6,3)#
C = #(4,1)#

Use the formula:

#d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}#

to work out the distance between individual points.

Use this to work out AB, AC, and BC.

Then add up the values.