How do you solve $\frac{3 (t - \frac{1}{3})}{2} - 4 = 6$ $(3(t-1/3))/2-4=6$ ?

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Answer 1 · 2018-05-15T23:27:52

$t = 7$ $t=7$

$\frac{3 (t - \frac{1}{3})}{2} - 4 = 6$ $(3(t-1/3))/2-4=6$
we want to isolate t

since the term containing t has 4 subtracted from it, we add 4 to both sides

adding 4 to both sides:
$\frac{3 (t - \frac{1}{3})}{2} = 10$ $(3(t-1/3))/2=10$

multiply both sides by 2 to get
$3 (t - \frac{1}{3}) = 20$ $3(t-1/3)=20$

the term containing t is being multiplied by 3, so we can divide both sides by 3 to get

$(t - \frac{1}{3}) = \frac{20}{3}$ $(t-1/3)=20/3$

finally, $\frac{1}{3}$ $1/3$ is being subtracted from t so we can add $\frac{1}{3}$ $1/3$ to both sides to get

t = $\frac{21}{3} = 7$ $21/3=7$

How do you solve (3(t-1/3))/2-4=63(t−13)2−4=6(3(t-1/3))/2-4=6?